![]() Unlike rotational or oscillatory motion, there’s no change in the direction of the moving object in linear motion. ![]() Question: What distinguishes linear motion from other types of motion? Answer: Linear motion refers to the movement of an object along a straight path in a single direction.Velocity increases = nonuniform linear motion, accelerated. V = velocity, s = distance, t = time interval V = velocity, s = distance, t = time intervalĬonstant velocity = uniform linear motion. Distance and time interval of a moving object shown in table below.ĭetermine t he types of motion experienced by objects 1 and 2… Three equation of motion at constant acceleration :ħ. After travels 150 meters, car’s velocity = 72 km/hour. An 800-kg car travels along a straight line with the initial velocity of 36 km/hour. Motion 3: Object decelerated for 10 seconds until rest.Ħ. Motion 2 : Object travels during 5 seconds until it’s velocity = 10 m/s. Motion 1 : Object travels at a constant 5 m/s in 10 seconds. Deceleration (a) and time interval (t) calculated using data of motion 3. Time interval calculated after find deceleration. The final velocity of motion 2 calculated using data of motion 2 :įinal velocity for motion 2 (v t) = initial velocity for motion 3 (v o) = 10 m/s Initial velocity (v o) = velocity in motion 1 = 5 m/s ![]() Motion 2 = motion at constant acceleration Which graph (v-t) shows the object’s travels. Then decelerated until rest after car travels 137.5 meters. A car travels at a constant 5 m/s in 10 seconds, then accelerated 1 m/s 2 in 5 seconds. Motion 3: Object decelerated in 10 seconds until rest.ĥ. Motion 2 : Object accelerated in 10 seconds until it’s speed = 20 m/s. Motion 1 : Object travels at a constant 10 m/s in 5 seconds Wanted : which graph shown object’s travelsįinal velocity of motion 2 (v t) = initial velocity of motion 3 (v o) = 20 m/s ![]() Initial velocity (v o) = velocity in motion 1 = 10 m/s An object travels at a constant 36 km/hour during 5 seconds, then accelerated 1 m/s 2 during 10 seconds and then decelerated 2 m/s 2 until rest. The distance traveled during 12 seconds = 4 + 16 + 4 + 4 + 8 = 36 metersĤ. time (t) for linear motion shown in figure below. Graph of linear motion shown in the figure below. What is the deceleration according to the graph.Ī-B = motion at constant acceleration, B-C = motion at constant velocity, C-D = motion at constant deceleration.Ģ.
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